I am trying to configure browser synch with gulp, i want to watch my scss files and get them compiled and saved in a folder called dist, when changes are made and I also want to reload my browser when this process is completed. so far I'm successful in watching, compiling and loading result in a new window but I can't get to refresh the browser window when ever further changes are made in the scss file..what am I doing wrong here? and I also want to know if this is the right way to do this.
here is my gulpfile.js
'use strict';
var gulp = require('gulp'),
scss = require('gulp-sass'),
maps = require('gulp-sourcemaps'),
browsersync = require("browser-sync");
gulp.task("ScssCompiler",function(){
gulp.src("scss/style.scss")
.pipe(maps.init())
.pipe(scss())
.pipe(maps.write('./'))
.pipe(gulp.dest('dist'));
console.log("entered ScssCompiler");
});
gulp.task("sass-watch",["ScssCompiler"],browsersync.reload);
gulp.task("watchsass",function(){
browsersync({
server:{
baseDir:'./',
}
});
gulp.watch(['scss/*.scss'],['sass-watch']);
console.log("entered watchsass");
});
gulp.task("build",['watchsass'],function(){
console.log("entered build");
});
gulp.task("default",['build'],function(){
});
you may look my code : which resolve all problems.
https://github.com/krmao/template/blob/gulp/build-script/Build.js