I calculated the FFT of array {1,2,3,4,5,6} with fftw/C++ and an online calculator (http://calculator-fx.com/calculator/fast-fourier-transform-calculator-fft/1d-discrete-fourier-transform). And the results seemed to be a bit different.
fftw output:
0 21.000000 0.000000 1 -3.000000 5.196152 2 -3.000000 1.732051 3 -3.000000 0.000000 4 0.000000 0.000000 5 0.000000 0.000000
Online calculator output:
21 + 0j -3 + 5.196152j -3 + 1.732051j -3 + 0j -3 - 1.732051j -3 - 5.196152j
As is shown above, the latter two results of fftw turned to be zero. Can't figure out why. Could anybody help me out? Thanks.
[EDITED] cpp code:
int main()
{
fftw_complex *out;
fftw_plan plan;
double arr[]={1,2,3,4,5,6};
int n = sizeof(arr)/sizeof(double);
out = (fftw_complex*)fftw_malloc ( sizeof ( fftw_complex ) * n );
plan = fftw_plan_dft_r2c_1d ( n, arr, out, FFTW_ESTIMATE );
fftw_execute ( plan );
for (int i = 0; i < n; i++ )
{
printf ( " %3d %12lf %12lf\n", i, out[i][0], out[i][1] );
}
fftw_free(out);
fftw_destroy_plan(plan);
return 0;
}
Oh, you're using the R2C mode (don't know why I didn't think of that before). That only writes n/2 + 1 results, because of the symmetry.
This behaviour is documented: http://www.fftw.org/doc/One_002dDimensional-DFTs-of-Real-Data.html.