I am wondering what the behavior of passing a Nullable<int> type to a generic method that accepts a T? (another Nullable<int> type). Here is the code in question:
int? myNullableParameter = 8;
MyGenericMethod(myNullableParameter);
void MyGenericMethod<T>(T? parameter)
{
//Do Something with parameter
Console.WriteLine($"{parameter}");
}
As this compiles fine here is the confusion. I am setting the type of myNullableParameter to Nullable<int>. Then I pass this type into the parameterized generic method as Nullable<T>. However, the type of the parameter is also a T? which gets resolved from the compiler to a Nullable<T>. So is it a Nullable<Nullable<int>>? Or does the compiler simply ignore this second Nullable<T> and keep the parameter inside the method as a Nullable<int>?
Thanks!
(My answer assumes you're using C# 9.0 or later)
Methinks you have a misconception; from here it looks like you think/understand/believe that when an unconstrained generic type
Tis annotated asT?then it means C#+CLR will handle value-typedTtype-arguments asNullable<T>and reference-typedTtype-arguments as[AllowNull]/[MaybeNull], including somehow marshalling non-nullvalue-types betweenT?andT.However the truth is... it doesn't.
Since C# 9.0, the generic-type syntax
T?(whenTis unconstrained) just means that:Tis a reference-type, then at-this-point, this T is possibly-null, i.e.[AllowNull]/[MaybeNull]"Tis aNullable<U>, then at-this-point,Tcould benull"nullableStruct.HasValue == falseT(not aT?) appears in the same scope, then that denotes a non-nullNullable<T>(i.e.value.HasValue == true).Tis a value-type (and notNullable<U>), then this T is a non-nullableTvalue-type".A demonstration:
Consider this method:
Case 1: Non-nullable-reference-type
T := StringIf we specify
T = Stringthen:nullableTeeparameter retains its?annotation, so it becomesString?.notNullableTeeparameter represents (non-nullable)String.So we have
void AcceptsAllegedlyNullableT<String>( String? nullableTee, String notNullableTee )such thatnullableTeeaccepts a maybe-nullStringreference andnotNullableTeedoes not....so far, so good.
Case 2: Nullable-reference-type
T := String?If we specify
T = String?, then thenullableTeeparameter won't beString??, but instead the annotations collapse down toString?...while
T notNullableTeeturns intoString? notNullableTee.So we have
void AcceptsAllegedlyNullableT<String?>( String? nullableTee, String? notNullableTee )such thatnullableTeeaccepts a maybe-nullStringreference - andnotNullableTeeis actually quite nullable....feeling awkward yet?
Case 3: (Non-nullable) value-type
T := Int32If we specify
T = Int32, then the?annotation onnullableTee's type is a lie because its static type remainsInt32and notNullable<Int32>.void AcceptsAllegedlyNullableT<Int32>( Int32 nullableTee, Int32 notNullableTee )such thatnullableTeecannot accept aNullable<Int32>, despite the?annotation, but at leastnotNullableTeeis accurately-named once again...?annotation should be interpreted as "maybe-default(T)" and not "maybe-null" - but those people live a in bubble.Case 4: Nullable-value-type
T := Nullable<Int32>(akaInt32?)If we specify
T = Nullable<Int32>(akaInt32?orint?), then the?annotation onnullableTee's type is basically ignored by everything now - and allTvalues are nullable too; so now we havevoid AcceptsAllegedlyNullableT<Nullable<Int32>>( Nullable<Int32> nullableTee, Nullable<Int32> notNullableTee )...so our
notNullableTeeis a liar-liar-type-system-on-fire.Here's what happens when you run such a program with those type-parameter arguments:
Console output: