XSS scan with python and selenium

Question

I am trying to make XSS scanner using selenium. First I tried checking for XSS with the response until I realized that is a poor way to check. I started using Selenium because I thought it would be better at interacting with pages and able to detect the alert box popping up. I built a vulnerable website with a simple form and tested it, but it just fills the form without causing the alert to popup, here is code i used

from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.common.by import By
import time

def check_xss(url, input_boxes):
    vulnerabilities = []
    
    payloads = [
        "<script>alert('XSS')</script>",
        "<img src='x' onerror='alert(\"XSS\")'>",
        "<svg/onload=alert('XSS')>",
        "<svg><script>alert('XSS')</script>",
        "'\"><script>alert('XSS')</script>",
        "';alert('XSS');//",
        "%3Cscript%3Ealert('XSS')%3C/script%3E"
    ]

   
    driver = webdriver.Chrome()
    
    try:
        for input_box in input_boxes:
            if 'name' in input_box.attrs:
                print(f"Testing for XSS on input box : {input_box['name']}")
                for payload in payloads:
              
                    driver.get(url)
                    
               
                    input_field = driver.find_element(By.NAME, input_box['name'])
                    
                  
                    input_field.send_keys(payload)
                    
                 
                    input_field.submit()
                    
      
                    time.sleep(1)
                    
          
                    try:
                        alert = driver.switch_to.alert
                        vulnerabilities.append({
                            'type': 'XSS',
                            'input_param': input_box['name'],
                            'payload': payload,
                            'result': f'XSS Success with payload : {payload}'
                        })
                        print(f"XSS Success with payload : {payload}")
                        alert.accept()  # Close the alert dialog
                    except:
                        pass  # No alert dialog appeared, so continue testing

    finally:
        # Close the browser
        driver.quit()

    if not vulnerabilities:
        print(f"No XSS vulnerability found for input box: {input_box['name']}")

    return vulnerabilities

With this it just fills the form and doesnt trigger the alert box, even though i know its XSS vulnernable and when maunually doing the attack the alert box appears.

How can I get this to actually check for XSS

I can't figure out how to make this work, ive tried increasing the timeout but it didnt do anything