See in the image i got a 1(min term) at the bottom right corner which I can't assign it to any groups . What should i do ? Should i leave this 1 as it is and do other simplification or i should count it as single group ?
What to do with an element if i can't assign it to any group in Karnaugh map?
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It would be: AB'CD' as those are the constant variables.
The larger the group, the less variables (ABCD) you will need to represent it.
It is considered an essential prime implicant (meaning that it is required to be represented as it can only be grouped in a single way) - therefore it has it's own grouping of 1 (in this case). Groupings work for powers of 2, so a grouping of a single element is the same as 2^0. You can have groupings of: 1,2,4,8, etc. This will be more relevant once you work on 5-variable or 6-variable K-Maps
You create groups with the size of 2^N elements, this includes the size
1.(1=2^0). So you create indeed a single group with only that single element atAB'CD'.