While trying to find a solution to another question ([1]) I came across a diverging implicit expansion error. I'm looking for an explanation about what this means
Here's the use case:
scala> implicit def ordering[T](implicit conv: T => Ordered[T], res: Ordering[Ordered[T]]) = Ordering.by(conv)
ordering: [T](implicit conv: (T) => Ordered[T],implicit res: Ordering[Ordered[T]])scala.math.Ordering[T]
scala> def foo[T <% Ordered[T]](s : Seq[T]) = s.sorted
<console>:6: error: diverging implicit expansion for type Ordering[T]
starting with method ordering in object $iw
def foo[T <% Ordered[T]](s : Seq[T]) = s.sorted
^
If you run this in scala with the
-Xlog-implicits
argument passed, you get more information:This is mostly speculation, but would seem to make some sense. I will try to investigate further:
This seems to suggest that there are three implicits that are being considered here. Ultimately, the signature of
sorted
requires it to find something of typeOrdering[T]
. So it's trying to construct your implicit functionordering
. Firstly, it's trying to fill inconv
by finding an implicit of type(T) => Ordered[T]
, where it's searching in Predef - which seems like barking up the wrong tree. It's then trying to find an implicit for(Ordered[T]) => Ordered[Ordered[T]]
in the same place, sinceby
takes an implicit parameter of typeOrdering[S]
, whereS
isOrdered[T]
by virtue ofconv
. So it can't constructordering
.It then tries to use
ordering
in math.Ordering, but this also doesn't fit. However, I think this is what's giving the somewhat confusing 'diverging implicits' message. The problem isn't that they're diverging, it's that there isn't a suitable one in scope, but it's being confused by the fact that there are two paths to go down. If one tries to definedef foo[T <% Ordered[T]](s : Seq[T]) = s.sorted
without the implicit ordered function, then it fails with just a nice message saying that it can't find a suitable implicit.