Using removeAll to remove a sublist from a list

Question

    List<Integer> list = new ArrayList<>();
    list.add(1);
    list.add(0);
    list.add(0);
    list.removeAll(list.subList(0, 1));
    System.out.println(list);

If I run this code, it gives [0].

    List<Integer> list = new ArrayList<>();
    list.add(1);
    list.add(0);
    list.add(1);
    list.removeAll(list.subList(0, 1));
    System.out.println(list);

This gives [0, 1]...

Why are they different? More importantly, why it gives [0] in the first case?