The code is a little complex, sorry. Please focus on the parallel_p
function. Although sign
is a tuple, Python complains:
if sign in hashtable
and gives a TypeError
. Why is sign
a numpy.ndarray
rather than a tuple? I created it as a tuple.
p_dist = dict()
def parallel_prog(hashtable):
def wrapper(func):
if parallel_programming:
@wraps(func)
def parallel_p(*args, **kwargs):
sign = tuple(args)
print type(sign)
if sign in hashtable:
r = hashtable[sign] # hit.
return r
r = func(*args, **kwargs)
hashtable[tuple(sign)] = r # register for future hits.
return r
return parallel_p
else:
return func
return wrapper
@parallel_prog(p_dist)
def euclidean(a, b, signature=None):
val = np.sqrt(np.add.reduce((a - b)**2))
return val
IN TEST MODULE
class similartyTest(unittest.TestCase):
def setUp(self):
self.t = np.array([1,2,3,4])
self.t1 = np.array([0, 0, 0, 0])
self.t2 = np.array([4,3,2,1])
self.h1 = [1,0,0,1,1]
self.h2 = [1,1,1,1,1]
def test_euclidean(self):
self.failUnless(euclidean(self.t, self.t) == 0)
self.failUnless(euclidean(self.t, self.t1) == sqrt(30))
OUTPUT:
<type 'tuple'>`
TypeError: unhashable type: 'numpy.ndarray`
Not every tuple is hashable. A tuple containing non-hashable items is not hashable:
Your tuple obviously contains a NumPy array, which is as far from being hashable as a type can be.