I want to get the producttype with admin info who added the producttype I am using sqlalchemy with postgresql and marshmallow
This is my Model related info related to Admin
class Admin(db.Model):
id = db.Column(db.Integer, primary_key=True)
full_name = db.Column(db.String())
email = db.Column(db.String(), unique=True)
mobile = db.Column(db.String(), unique=True)
password = db.Column(db.String())
product_types: db.relationship("ProductType", backref="admin", lazy=True)
created_at = db.Column(DateTime(timezone=True), server_default=func.now())
updated_at = db.Column(DateTime(timezone=True), onupdate=func.now())
def __repr__(self):
return "<Admin %r>" % self.full_name
class AdminSchema(ma.SQLAlchemyAutoSchema):
class Meta:
model = Admin
admin_schema = AdminSchema()
admins_schema = AdminSchema(many=True)
This is my Model related info related to Product_Type
class ProductType(db.Model):
id = db.Column(db.Integer, primary_key=True)
name = db.Column(db.String())
descripton = db.Column(db.String())
added_by_id = db.Column(db.Integer, db.ForeignKey("added_by.id"))
added_by: db.relationship("Admin", backref=db.backref("admin", lazy="dynamic"))
created_at = db.Column(DateTime(timezone=True), server_default=func.now())
updated_at = db.Column(DateTime(timezone=True), onupdate=func.now())
def __repr__(self):
return "<ProductType %r>" % self.name
class ProductTypeSchema(ma.SQLAlchemyAutoSchema):
class Meta:
model = ProductType
added_by = ma.Nested(AdminSchema)
product_type_schema = ProductTypeSchema()
product_types_schema = ProductTypeSchema(many=True)
If anyone can suggest something please do
I want to get the producttype with admin info who added the producttype I am using sqlalchemy with postgresql and marshmallow.
The output I am expecting
product_type:{
"created_at": "2023-01-21T07:55:14.773346+05:30",
"descripton": "Product Type",
"id": 6,
"name": "dgd",
"updated_at": null,
"admin":{
"full_name":""
"email":""
"mobile":""
}
}
Unfortunately, your code contains syntax errors as well as an inaccurate definition of the database relationships. For this reason it is difficult to interpret exactly what your database looks like or which renaming the schemas must contain.
As a note on defining relationships:
The following example shows a possible implementation to achieve the output you are aiming for.