Please look at the following code snippet and let me know what's wrong with that as I'm getting the below errors when trying to run it.
org.apache.jasper.JasperException: The jsp:param action must not be used outside the jsp:include, jsp:forward, or jsp:params elements
org.apache.jasper.JasperException: Expecting "jsp:param" standard action with "name" and "value" attributes
Here's the code I'm trying to execute
<%
String contextRoot = request.getContextPath();
String stdInfoViewURL = contextRoot.concat("jsp/student/ViewStudentDetails.jsp"):
%>
<html><body>
<jsp:include page="<%=stdInfoViewURL%>" flush="true">
<jsp:param name="studentId" value="ABC123" />
<jsp:param name="studentName" value="MARK TAYLOR" />
</jsp:include>
</body></html>
I tried even declaring the java objects in following manner too. But no luck.
<%!
String contextRoot = request.getContextPath();
String stdInfoViewURL = contextRoot.concat("jsp/student/ViewStudentDetails.jsp"):
%>
Omit the
contextRootfrom yourstdInfoViewURLand just doString stdInfoViewURL = "/jsp/student/ViewStudentDetails.jsp":