Integer division in PowerShell

Question

What is the easiest way to do integer division in PowerShell? So that the arguments are integers and the result is also an integer.

In C++ it would be e.g. 115/10.

Answer 1

For true integer division, use System.Math.Truncate and cast the result to [int]:

[int] [Math]::Truncate(115 / 10) # -> 11

Alternatively, use System.Math.DivRem, which directly returns an [int] (or [long]):

[Math]::DivRem(115, 10, [ref] $null) # -> 11

In PowerShell (Core) 7+, additional, integer-type specific overloads are available that return tuples, so you may alternatively use:

# PowerShell 7+ only.
[Math]::DivRem(115, 10)[0] # -> 11

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PowerShell widens numerical types on demand, and switches to [double] for division with integer operands (of any integer type, such as [int]) that would yield a remainder.

Casting to the result of a division to [int] (e.g. [int] (115 / 10)) is not the same as using [Math]::Truncate(), as that performs half-to-even rounding - see this answer for details.