Perhaps its possible to add an additional for loop around each return, and so wrap the result with a node?
Modifying a w3 schools sample query:
nicholas@mordor:~/flwor$
nicholas@mordor:~/flwor$ basex bookstore.category.name.xq
<xml>
<category>cooking</category>
<title>Everyday Italian</title>
<category>children</category>
<title>Harry Potter</title>
<category>web</category>
<title>Learning XML</title>
<category>web</category>
<title>XQuery Kick Start</title>
</xml>nicholas@mordor:~/flwor$
nicholas@mordor:~/flwor$
nicholas@mordor:~/flwor$ cat bookstore.category.name.xq
xquery version "3.1";
<xml>
{
for $x in db:open("bookstore")/bookstore/book
order by $x/title
return (<category>{data($x/@category)}</category>,<title>{data($x/title)}</title>)
}
</xml>
nicholas@mordor:~/flwor$
how can I wrap each result with a book element?
The xml
sample data:
<bookstore>
<book category="cooking">
<title lang="en">Everyday Italian</title>
<author>Giada De Laurentiis</author>
<year>2005</year>
<price>30.00</price>
</book>
<book category="children">
<title lang="en">Harry Potter</title>
<author>J K. Rowling</author>
<year>2005</year>
<price>29.99</price>
</book>
<book category="web">
<title lang="en">XQuery Kick Start</title>
<author>James McGovern</author>
<author>Per Bothner</author>
<author>Kurt Cagle</author>
<author>James Linn</author>
<author>Vaidyanathan Nagarajan</author>
<year>2003</year>
<price>49.99</price>
</book>
<book category="web">
<title lang="en">Learning XML</title>
<author>Erik T. Ray</author>
<year>2003</year>
<price>39.95</price>
</book>
</bookstore>
from the w3schools site.
Something like this should do it:
Output: