Consider the following template recursion function. Its purpose is to create a vector containing all values in the enum class EnumClassName for which its associated predicate function bool xxx<N>() returns true.
template <EnumClassName N = EnumClassName::LAST_ENUM_VALUE>
std::vector<EnumClassName> xxx_stuff()
{
std::vector<EnumClassName> v = xxx_stuff<EnumClassName(static_cast<int>(N) - 1)>();
if (xxx<N>()) {
v.emplace_back(N);
}
return v;
}
with the recursion base case:
template <> std::vector<EnumClassName> xxx_stuff<EnumClassName::FIRST_ENUM_VALUE>()
{
return {};
}
Now assume there are 10 of these functions where the only thing that differs is the xxx name. I.e. we have the functions alpha_stuff with a corresponding predicate function alpha<N>, beta_stuff with a corresponding predicate function beta<N>, etc etc.
Is there any way to not duplicate the above function 10 times, where the only difference is the replacement of xxx with alpha, beta etc in each duplicate?
I am not able to just loop over the enum values, because the xxx<N> functions in turn call another function yyy<N> which will not accept a runtime-generated template argument <N> (forgive my lingo there, I actually have no idea what I'm talking about or how this works, I just know it gave me compilation errors when I tried it that way).
You cannot pass function template as argument or overloaded function, but you can wrap the call in a type, and then
with usage
Demo
Note: That recursion can be avoided using
std::integer_sequence.