I get this Disassembly code on Visual Studio IDE's Debugger, from a C++ build:
For what I see on movss instruction, it should be
- F3 0F 10 /r MOVSS xmm1, xmm2 -- Merge scalar single precision floating-point value from xmm2 to xmm1 register.
- F3 0F 10 /r MOVSS xmm1, m32 - Load scalar single precision floating-point value from m32 to xmm1 register.
- F3 0F 11 /r MOVSS xmm2/m32, xmm1 -- Move scalar single precision floating-point value from xmm1 register to xmm2/m32.
So, while first 3 bytes are easy to understand, I don't really understand the rest, such as 05 6b 02 10 00 for the first row, 44 24 38 for the second, and so on.
Can you help me to understand them? 05 or 44 seems /r? What does it means?

You will need the official pdf version of the IntelĀ® 64 and IA-32 Architectures Software Developer's Manual Volume 2: Instruction Set Reference, A-Z.
Consult the chapter "3.1.1.1 Opcode Column in the Instruction Summary Table (Instructions without VEX Prefix)" which says:
Then look in the Table 2-2. 32-Bit Addressing Forms with the ModR/M Byte, find the value
05. It is in thexmm0column and thedisp32row. This means a 32 bit displacement will follow. Finally see Table 2-7. RIP-Relative Addressing which says thatdisp32is repurposed to meanRIP + Disp32in 64 bit mode. Hence the6B 02 10 00meanRIP + 0010026Bwhich is helpfully (?) decoded by the disassembler as7FFB47521775 + 0010026B = 7FFB476219E0For the second instruction, you will find the
44in columnxmm0, row[--][--]+disp8which according to the footnote means:So the next byte is a SIB. You can see those in Table 2-3. 32-Bit Addressing Forms with the SIB Byte. The value
24is in columnesp, rownone. Adjusting for 64 bit this means the address is in the form of[rsp + disp8]with the displacement given by the following byte which is38.