I have a gulp.src stream with files:
file.cwd file.base file.path
D:\Projects\test D:\Projects\test\public\app\ D:\Projects\test\public\app\bootstrap-8843d1ff.js
D:\Projects\test D:\Projects\test\public\app\contacts\views\index\ D:\Projects\test\public\app\contacts\views\index\contacts-4173bf62.js
D:\Projects\test D:\Projects\test\public\app\homepage\views\index\ D:\Projects\test\public\app\homepage\views\index\homepage-1eb3581b.js
D:\Projects\test D:\Projects\test\public\app\user\resources\ D:\Projects\test\public\app\user\resources\user-f75d774a.js
D:\Projects\test D:\Projects\test\public\ D:\Projects\test\public\index.html
I want save files as:
gulp.dest('test\build') ->
test\build\app\bootstrap-8843d1ff.js
test\build\app\contacts-4173bf62.js
test\build\app\homepage-1eb3581b.js
test\build\app\user-f75d774a.js
test\build\index.html
How do I rename the cwd, base and path in the stream, to save as I need it?