Get an error when calling a function from a different include_once file?

Question

I have a structure like so:

main.php

include_once func1.php

include_once func2.php

These two files are include'd inside main.php.

I get the error below when I call a function switchboard() from func1.php inside finc2.php.

Fatal error:  Uncaught Error: Call to a member function switchboard() on null in func2.php:16
Stack trace:
#0 main.php(60): decode_func('{"auth":"...)
#1 {main} thrown in func2.php on line 16

Line 16 is where I call the function from func1.php inside func2.php — switchboard() {}. Is there a way to fix this besides includeing func1.php inside func2.php?

---

func2.php

 function decode($var) {

     if() {return $var;} 
     else { $erm->switchboard('101', $var); }   
 }

func1.php

 $erm = new CLASS() {

   function switchboard($id, $var) {

     if() {}
     else {}
   }

 }

Answer 1

That would be because you use $erm in the function decode(), yet it is not included in the function's scope (let's keep in mind that contrarily to javascript, php functions do not inherit their surrounding scope)

You can declare decode as an anonymous function and take advantage of use to inject $erm inside it, or make $erm an argument of decode.

• Anonymous function

Just use $erm to make sure to include it inside decode's scope:

$decode = function ($var) use ($erm) {
    if() { return $var; } 
    else { $erm->switchboard('101', $var); }   
};

• Parameter

Pass $erm like any other parameter.

function decode ($var, $erm) {
    if(false) { return $var; } 
    else { $erm->switchboard('101', $var); }   
}