Django Imagekit processing the original image

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With version 1.1 I don't understand how I can preprocess the original image (by JUST using imagekit)

https://github.com/jdriscoll/django-imagekit/blob/develop/README.rst

Having a model like this:

class Photo(models.Model):
   original = models.ImageField(etcetera)
   thumbnail = ImageSpec(etcetera)

How do I for instance resize the original image? This was possible in previous imagekits, however the documentation insinuates I need another modelfield?

3

There are 3 answers

0
matthewwithanm On BEST ANSWER

You can use ProcessedImageField:

from imagekit.models import ProcessedImageField

class Photo(models.Model):
    original = ProcessedImageField(etcetera)

There is in-code documentation on this class, but it looks like it's not being picked up by readthedocs' autodoc module right now.

I reopened a bug to fix the documentation.

2
sgallen On

Looking here: https://github.com/jdriscoll/django-imagekit/blob/master/imagekit/processors/resize.py it looks like the Fit class is what you're after.

Untested but I suspect it's something like:

from django.db import models
from imagekit.models import ImageSpec
from imagekit.processors import resize

class Photo(models.Model):
    original_image = models.ImageField(upload_to='photos')
    thumbnail = ImageSpec([resize.Fit(50, 50)], image_field='original_image',
            format='JPEG', options={'quality': 90})
0
Val Neekman On

Below will do what you are looking for. You can add other processors to the list of processors as well. The processors are run prior to saving the image.

from imagekit.models import ProcessedImageField
from imagekit.processors import ResizeToFit

class Photo(models.Model):
    original = ProcessedImageField(
        upload_to='images/%Y%m',
        format=JPEG,
        processors=[ResizeToFit(200, 100)],
        options={'quality': 90}
    )