Given a BigInteger in Kotlin that is in the range between 0 and 2^64, how can I convert this BigInteger to a ULong? Kotlin provides toULong() extension methods only for Byte/Short/Int/Long/Float/Double.
Convert BigInteger to ULong in Kotlin
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You can safely do
bigint.toLong().toULong().The
toLong()extension callsBigInteger.longValue(). The documentation for that says "if this BigInteger is too big to fit in a long, only the low-order 64 bits are returned".Then the
Long.toULong()extension is documented as "The resulting ULong value has the same binary representation as this Long value."So with those two together, we can see that
toLong().toULong()will preserve all 64 bits of a BigInteger between 0 and 2^64-1.