Android SortedList java.lang.IndexOutOfBoundsException: Asked to get item at 0 but size is 0

Question

public Order gimmeThePendingOrderToDeliver(String _id, String my_phone) {
        for (int i = 0; i < orderSortedList.size(); i++) {
            Order o = orderSortedList.get(i);

            boolean a = o.isCanceled_by_user(), b = o.isCanceled_by_owner(), c = o.isDelivered();
            String d = o.getDelivery_guy();
            if (_id.equals(o.get_id()) && !a && !b && !c && d.equals(my_phone)) {
                Toast.makeText(context, "IM HERE", Toast.LENGTH_SHORT).show();
                return o;
            }
        }
        Toast.makeText(context, orderSortedList.get(0).get_id(), Toast.LENGTH_SHORT).show();
        return null;
    }

cant iterate Android SortedList returns error as descriped in the title ,, any help will be appreciated . THANKS in advance.

Answer 1

When orderSortedList is empty, it doesn't enter the for loop, and thus, it immediately reaches the bottommost Toast statement where orderSortedList.get(0) produces an IndexOutOfBoundsException since the list is empty.