Imagine situation, when the url should looks like
where page param is optional.
Of course, custom route should be defined. Consider the following code:
$route = new Zend_Controller_Router_Route_Regex(
'catalog/([-a-z]+)(?:\?page=([0-9]*))?',
array('controller'=>'catalog','action'=>'list','page'=>''),
array(1=>'section',2=>'page'),
'catalog/%s?page=%d'
);
$router->addRoute('catalog-section-page',$route);
But this route won't be triggered with '?' symbol in url.
Without '?' (for example, by adding escaped '!' symbol to pattern) everything works as it should. Is there any way to achieve '?' presence in custom defined regex route? Maybe I'm doing something wrong in pattern?
P.S.: Don't offer to use '/' instead of '?', question is exactly about pattern restrictions in Zend_Controller_Router_Route_Regex implementation.
The ZF routing classes operate on the REQUEST_URI with the query string stripped off, so you may have a hard time get this working in the way you are expecting. However, I believe GET parameters are put into the request object by default, so you shouldn't need to cater for them in your routes. I'd suggest changing your route to remove the query string parts:
You should still be able to access the params in your controller as if they had been populated by the routes:
and you can use the same method to set a default:
You just may need to sanitise them there (make sure they are numeric).
Edit:
Example of URL helper with this route: