WPF Callout Anchor start position

Question

I have implement Callout control of Blend. Problem which I am facing is anchor point of the Callout starts with some margin from the top, While I want to have anchor from the top left of the callout. Any help will be appreciated.

What I have now:

What I would like to have:

Answer 1

You seem to be mistaken about using this control. From MSDN, the Callout.AnchorPoint property Gets or sets the position of the callout relative to the top and left corner. It is used for positioning the control and does not alter the shape of the Callout.

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UPDATE >>>

Dude!!! That's a really simple shape... just draw your own one with a Path... then you can make it any shape you want:

<Path Stroke="Black" StrokeThickness="1" Fill="#CCCCFF">
    <Path.Data>
        <CombinedGeometry GeometryCombineMode="Union">
            <CombinedGeometry.Geometry1>
                <RectangleGeometry RadiusX="20" RadiusY="20" Rect="0,0,300,200">
                    <RectangleGeometry.Transform>
                        <TranslateTransform X="30" />
                    </RectangleGeometry.Transform>
                </RectangleGeometry>
            </CombinedGeometry.Geometry1>
            <CombinedGeometry.Geometry2>
                <PathGeometry>
                    <PathFigure StartPoint="0,30">
                        <LineSegment Point="50,10" />
                        <LineSegment Point="50,50" />
                    </PathFigure>
                </PathGeometry>
            </CombinedGeometry.Geometry2>
        </CombinedGeometry>
    </Path.Data>
    <Path.Effect>
        <DropShadowEffect Color="Black" Opacity="0.4" Direction="-135"
            ShadowDepth="10" />
    </Path.Effect>
</Path>