Will the compiler strip the unrelated arch symbols from dependent static library in product binary file?

763 views Asked by At

I'm a new in framework development, here is my case. I build a private static library to provide it to the vendors to link it.

Currently, I build my library with arch armv7 and arm64 only, this should be work for vendors to debug it in iOS device and archive their apps, but not for debugging in iOS Simulator. The simulator needs the x86_64 ( and even i386 in iPhone 5 Simulator). It isn't friendly to disable the ability to debug it in a simulator. I'm considering to provide a fat architecture of static library for them.

Here is the action

lipo -create libSignatureLibary_armv6.a libSignatureLibary_armv7.a libSignatureLibary_i368.a -output libSignatureLibary.a

After the merge operation, the output library has a double size than the single one.

The question is, will the compiler/Xcode strip the i386 and x86_64 arch symbols from final app product binary? If not, the fat arch library will increase the product app's size directly, right? Should I build two versions of the library for vendors, one for debugging, another for archiving? What's the right solution for this case?

I don't know what keywords I should research, I didn't have an existing product app linking it to verify this, either. (Maybe I should build a new later.)

1

There are 1 answers

7
KudoCC On BEST ANSWER

Don't worry, the linker only uses the .o (relocatable object file, it is the output file of assembler, when you build a static library, a .m file will be translated to a .o file. The static library is a collection of relocatable object files) files for target arch in the static library, so it will strip the x86_64 and i386 .o files when building product binary.

Also the linker won't link the .o file which is not referenced directly or indirectly by compiled files into executable file.