I wrote a simple program to sort out my array. The problem is that the code works with int values only while I need my array to have double
elements ... Any help?
#include <stdio.h>
#include <stdlib.h>
double values[] = { 88, 56, 100, 2, 25 };
int cmpfunc (const void * a, const void * b)
{
return ( *(int*)a - *(int*)b );
}
int main()
{
int n;
printf("Before sorting the list is: \n");
for( n = 0 ; n < 5; n++ )
{
printf("%.2f ", values[n]);
}
printf("\n\n");
qsort(values, 5, sizeof(double), cmpfunc);
printf("\nAfter sorting the list is: \n");
for( n = 0 ; n < 5; n++ )
{
printf("%.2f ", values[n]);
}
printf("\n\n");
return(0);
}
WORKING CODE:
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
double values[] = { 88, 56, 100, 2, 25 };
int compare (const void * a, const void * b)
{
if (*(double*)a > *(double*)b) return 1;
else if (*(double*)a < *(double*)b) return -1;
else return 0;
}
int main()
{
int n;
printf("Before sorting the list is: \n");
for( n = 0 ; n < 5; n++ )
{
printf("%.2f ", values[n]);
}
printf("\n\n");
qsort(values, 5, sizeof(double), compare);
printf("\nAfter sorting the list is: \n");
for( n = 0 ; n < 5; n++ )
{
printf("%.2f ", values[n]);
}
printf("\n\n");
return(0);
}
You want to sort doubles but you compare them as ints... Try this comparison function: