Why fusion::map<> types not the same

110 views Asked by At

Why type is not same as expected in the example below?

using origin = boost::fusion::map<
    boost::fusion::pair<int, int>
>;
using expected = boost::fusion::map<
     boost::fusion::pair<int, int>
    ,boost::fusion::pair<char, char>
>;

using type = boost::fusion::result_of::push_back<
     origin
    ,boost::fusion::pair<char, char>
>::type;

static_assert(std::is_same<expected, type>::value, "error!");

The second question is, how can I get the same type as expected when using result_of::push_back<>::type ?

1

There are 1 answers

1
niXman On BEST ANSWER

You need to use fusion::result_of::as_map.

using origin = boost::fusion::map<
    boost::fusion::pair<int, int>
>;
using expected = boost::fusion::map<
     boost::fusion::pair<int, int>
    ,boost::fusion::pair<char, char>
>;

using type = typename boost::fusion::result_of::as_map<
    typename boost::fusion::result_of::push_back<
         origin
        ,boost::fusion::pair<char, char>
    >::type
>::type;