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This is not a duplicate of Assignment inside lambda expression in Python, i.e., I'm not asking how to trick Python into assigning in a lambda expression.

I have some λ-calculus background. Considering the following code, it looks like Python is quite willing to perform side-effects in lambda expressions:


def applyTo42(f):
    return f(42)

def double(x):
    return x * 2

class ContainsVal:
    def __init__(self, v):
        self.v = v

    def store(self, v):
        self.v = v

def main():

    print('== functional, no side effects')

    print('-- print the double of 42')

    print('-- print 1000 more than 42')
    print(applyTo42(lambda x: x + 1000))

    print('-- print c\'s value instead of 42')
    c = ContainsVal(23)
    print(applyTo42(lambda x: c.v))

    print('== not functional, side effects')

    print('-- perform IO on 42')
    applyTo42(lambda x: print(x))

    print('-- set c\'s value to 42')
    applyTo42(lambda x:

    #print('== illegal, but why?')
    #print(applyTo42(lambda x: c.v = 99))

if __name__ == '__main__':

But if I uncomment the lines

    print('== illegal, but why?')
    print(applyTo42(lambda x: c.v = 99))

I'll get

SyntaxError: lambda cannot contain assignment

Why not? What is the deeper reason behind this?

  • As the code demonstrates, it cannot be about “purity” in a functional sense.

  • The only explanation I can imagine is that assignemts do not return anything, not even None. But that sounds lame and would be easy to fix (one way: make lambda expressions return None if body is a statement).

Not an answer:

  • Because it's defined that way (I want to know why it's defined that way).

  • Because it's in the grammar (see above).

  • Use def if you need statements (I did not ask for how to get statements into a function).

“This would change syntax / the language / semantics” would be ok as an answer if you can come up with an example of such a change, and why it would be bad.

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