I'm in trouble, I am failing to understand why this error is happening.
So when I only run this code,
function getClientProject($cliente)
{
$file = fopen("Projetos.csv","r");
$ArrayCount = 0;
$bool = false;
while(! feof($file))
{
$data = fgetcsv($file);
if($data[0] != '')
{
if(substr_compare($data[0],$cliente, 0, 3) == 0)
{
if($ArrayCount > 0)
{
$total = count($OpenProject);
for($i=0;$i<$total;$i++)
{
if($OpenProject[$i] == $data[0])
$bool = true;
}
if($bool == false)
{
$OpenProject[$ArrayCount] = $data[0];
$ArrayCount++;
}
}else
{
$OpenProject[$ArrayCount] = $data[0];
$ArrayCount++;
}
}
}
}
fclose($file);
return $OpenProject;
}
It works and returns the Array. But when I call the function this way,
include_once 'CRM files/TSread.php';
$arrayC = getClientProject('SLA');
var_dump($arrayC);
No longer works and me these errors,
What am I doing wrong?
path, the file i'm using is "Projeto.php":
and my CRM files folder:
You are opening the file using a relative path. You assume that
Projetos.csv
is always in the same directory as theTSread.php
file. Although, when including it, you seem to be in a higher directory (outside of the CRM files directory), therefor PHP can no longer find your CSV file, since it's trying to open it relative to the upper directory now.You could pass the full path to your
getClientProject
method to avoid this. So, you would get something like:Obviously, you will need to change your function a little to work with this new constructor, so it should like something like this: