I am learning about new C++11 feature - uniform initialization. Wrote small program:
#include <iostream>
using namespace std;
class C {
public:
C(int a = 1, int b = 2) : a_{a}, b_{b}, n{0,1,2,3,4} {};
int n[5];
int a_,b_;
};
int main()
{
C c = C{}; // should call C(int a = 1, int b = 2) with default arg.
cout << c.a_ << " " << c.b_ << endl;
return 0;
}
However, I am getting unexpected result 0 0
. In other words, everything is initialized to zero. The only way this could have happened: 1. Implicit default constructor was called, or 2. Initialization was not done correctly. (3. Compiler ???)
Why am I getting unexpected results ? Were there any changes to Constructor syntax that uses Uniform initialization in C++11 ?
EDIT: Using latest Intel Compiler:
1>------ Rebuild All started: Project: Unif_Init (Intel C++ 13.0), Configuration: Debug Win32 ------
1> Source.cpp
1> xilink: executing 'link'
1> xilink: executing 'link'
1> Unif_Init.vcxproj -> C:\Users\alex\documents\visual studio 2012\Projects\Unif_Init\Debug\Unif_Init.exe
========== Rebuild All: 1 succeeded, 0 failed, 0 skipped ==========
That's a bug in the compiler.
C{}
calls the default constructor to create a temporary which is used to copy-initialize the objectc
.C(int a = 1, int b = 2)
is obviously a default one so it should use that. Does switching the initialization order to the order declared in the class help (probably not, but just a guess)? It seems the intel compiler isn't considering your ctor with default arguments as the default one.