Time duration to string 2h instead 2h0m0s

22.8k views Asked by At

The default time.Duration String method formats the duration with adding 0s for minutes and 0m0s for hours. Is there function that I can use that will produce 5m instead 5m0s and 2h instead 2h0m0s ... or I have to implement my own?

2

There are 2 answers

0
icza On BEST ANSWER

Foreword: I released this utility in github.com/icza/gox, see timex.ShortDuration().


Not in the standard library, but it's really easy to create one:

func shortDur(d time.Duration) string {
    s := d.String()
    if strings.HasSuffix(s, "m0s") {
        s = s[:len(s)-2]
    }
    if strings.HasSuffix(s, "h0m") {
        s = s[:len(s)-2]
    }
    return s
}

Testing it:

h, m, s := 5*time.Hour, 4*time.Minute, 3*time.Second
ds := []time.Duration{
    h + m + s, h + m, h + s, m + s, h, m, s,
}

for _, d := range ds {
    fmt.Printf("%-8v %v\n", d, shortDur(d))
}

Output (try it on the Go Playground):

5h4m3s   5h4m3s
5h4m0s   5h4m
5h0m3s   5h0m3s
4m3s     4m3s
5h0m0s   5h
4m0s     4m
3s       3s
0
Tarion On

You can just round the duration like this:

        func RountTime(roundTo string, value time.Time) string {
            since := time.Since(value)
            if roundTo == "h" {
                since -= since % time.Hour
            }
            if roundTo == "m" {
                since -= since % time.Minute
            }
            if roundTo == "s" {
                since -= since % time.Second
            }
            return since.String()
        }