I am asking this question based on the answers in this link
POST request via RestTemplate in JSON
I actually wanted to send JSON from client and receive the same at REST server. Since the client part is done in the link I mentioned above. For the same how would I handle that request at server end.
CLIENT:
// create request body
JSONObject request = new JSONObject();
request.put("username", name);
request.put("password", password);
// set headers
HttpHeaders headers = new HttpHeaders();
headers.setContentType(MediaType.APPLICATION_JSON);
HttpEntity<String> entity = new HttpEntity<String>(request.toString(), headers);
// send request and parse result
ResponseEntity<String> loginResponse = restTemplate
.exchange(urlString, HttpMethod.POST, entity, String.class);
if (loginResponse.getStatusCode() == HttpStatus.OK) {
JSONObject userJson = new JSONObject(loginResponse.getBody());
} else if (loginResponse.getStatusCode() == HttpStatus.UNAUTHORIZED) {
// nono... bad credentials
}
SERVER:
@RequestMapping(method=RequestMethod.POST, value = "/login")
public ResponseEntity<String> login(@RequestBody HttpEntity<String> entity) {
JSONObject jsonObject = new JSONObject(entity.getBody());
String username = jsonObject.getString("username");
return new ResponseEntity<>(username, HttpStatus.OK);
}
This gives me 400 bad request error at client side. Hoping for some clues about how to handle this at server side.
HTTPEntity should not be used in your server method. Instead use the argument which is being passed to HTTPEntity from your client. In your case it has to String since you are passing string from client. Below code should work for you.
My advice is to create bean class and use it in server and client instead of converting it to String. It will improve readability of the code.