Shell Script with conditional clauses for script output

Question

I am new this site as well as new to shell scripting and this is my first form. Please help me with the following shell script.

I am executing a shell script to run every 15 min (scheduled in cronjob) and it gives an output in an output file which is e-mailed.

CONCCOUNT=`cat $OUT_DIR/EBS_Locked_Accounts.out|grep INVALID |wc -l`
echo $CONCCOUNT

if [ $CONCCOUNT != 0 ]
then
outputFile="$OUT_DIR/EBS_Locked_Accounts.out"
(
echo "From: [email protected]"
echo "To: $MAILLIST"
echo "MIME-Version: 1.0"
echo "Subject: Locked Accounts in EBS"
echo "Content-Type: text/html"
cat $outputFile
) | sendmail -t

My requirement is:

I don't want the script to send output every 15 min (cannot change the cronjob schedule) instead it should send the actual output every one hour unless there is a change in the count.

Answer 1

It you can't change the cronjob schedule, you can create a file that counts to 4 and then sends it and resets the count, since 15 minutes*4 = 1 hour. Like this:

echo "1" > croncount.txt

#!/usr/bin/bash
CRONCNT=$(cat "croncount.txt")
if [ $CRONCNT == 4 ]; then
    if [ $CONCCOUNT != 0 ]; then 
    outputFile="$OUT_DIR/EBS_Locked_Accounts.out" ( echo "From: [email protected]" echo "To: $MAILLIST" echo "MIME-Version: 1.0" echo "Subject: Locked Accounts in EBS" echo "Content-Type: text/html" cat $outputFile ) | sendmail -t
    fi    
    echo "1" > croncount.txt
else
    CRONCNT=$((CRONCNT+1))
    echo "$CRONCNT" > croncount.txt
fi