I have the following traits to detect if two type are divisible, and return the resulting operation type or another Default
type otherwise:
struct default_t { };
// Overloaded template for fallbacks
template <class U, class V>
default_t operator/(U, V);
// If the expression std::declval<U>()/std::declval<V>() is valid,
// gives the return type, otherwize provide Default.
template <class U, class V, class Default>
struct div_type_or {
using type_ = decltype(std::declval<U>() / std::declval<V>());
using type = typename std::conditional<
std::is_same<type_, default_t>{},
Default,
type_>::type;
};
template <class... Args>
using div_type_or_t = typename div_type_or<Args...>::type;
This works well with libstdc++, but not with libc++, when I try with a non-divisible std::chrono::duration
type, e.g.:
struct A { };
div_type_or_t<std::chrono::seconds, A, int> b;
I get the following error:
/Library/Developer/CommandLineTools/usr/include/c++/v1/chrono:764:81: error: no type named 'type' in 'std::__1::common_type' typename common_type::type>::value> ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~^~~~
/Library/Developer/CommandLineTools/usr/include/c++/v1/chrono:777:7: note: in instantiation of default argument for '__duration_divide_imp >, A>' required here : __duration_divide_imp, _Rep2> ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ >
/Library/Developer/CommandLineTools/usr/include/c++/v1/chrono:784:10: note: in instantiation of template class 'std::__1::chrono::__duration_divide_result >, A, false>' requested here typename __duration_divide_result, _Rep2>::type ^
test.cpp:16:46: note: while substituting deduced template arguments into function template 'operator/' [with _Rep1 = long long, _Period = std::__1::ratio<1, 1>, Rep2 = A] using type = decltype(std::declval() / std::declval()); ^
test.cpp:24:1: note: in instantiation of template class 'div_type_or >, A, D>' requested here using div_type_or_t = typename div_type_or::type; ^
test.cpp:48:19: note: in instantiation of template type alias 'div_type_or_t' requested here div_type_or_t, D>{}, "");
As I understand this, it is because the following overload of operator/
for std::chrono::duration
fails:
template< class Rep1, class Period, class Rep2 >
duration<typename std::common_type<Rep1,Rep2>::type, Period>
constexpr operator/( const duration<Rep1, Period>& d,
const Rep2& s );
I thought that since the std::common_type
is part of the function signature, this would allow SFINAE to work and use my custom overload of operator/
and thus deduce default_t
, but apparently this does not work...
Since this works with libstdc++, I just wanted to know if there was an issue with my code (maybe I did not understand the way SFINAE would work in this case) or if this was a libc++ bug?
In libc++, we have:
So instead of
std::common_type<_Rep1, _Rep2>::type
,they use
__duration_divide_result<duration<_Rep1, _Period>, _Rep2 /*, false*/>
,which instantiates
__duration_divide_imp<duration<_Rep1, _Period>, _Rep2 /*, is_convertible<_Rep2, typename common_type<_Rep1, _Rep2>::type>::value*/>
That usage is an hard error.
I would say that implementation in libc++ is incorrect in that regard.