I want to remove a pattern with sed, only at second occurence. Here is what I want, remove a pattern but on second occurrence.
What's in the file.csv:
a,Name(null)abc.csv,c,d,Name(null)abc.csv,f
a,Name(null)acb.csv,c,d,Name(null)acb.csv,f
a,Name(null)cba.csv,c,d,Name(null)cba.csv,f
Output wanted:
a,Name(null)abc.csv,c,d,Name,f
a,Name(null)acb.csv,c,d,Name,f
a,Name(null)cba.csv,c,d,Name,f
This is what i tried:
sed -r 's/(\(null)\).*csv//' file.csv
The problem here is that the regex is too greedy, but i cannot make is stop. I also tried this, to skip the first occurrence of "null":
sed -r '0,/null/! s/(\(null)\).*csv//' file.csv
Also tried but the greedy regex is still the problem.
sed -r 's/(\(null)\).*csv//2' file.csv
I've read that ?
can make the regex "lazy", but I cannot make it workout.
sed -r 's/(\(null)\).*?csv//' file.csv
The more robust awk solution:
Extended sample file
input.csv
:The job:
The output: