My question popped out while reading the tutorials on SDL2, on lazyfoo.net and the code is being copied from this page
int main( int argc, char* args[] )
{
//Start up SDL and create window
if( !init() )
{
printf( "Failed to initialize!\n" );
}
else
{
//Load media
if( !loadMedia() )
{
printf( "Failed to load media!\n" );
}
else
{
//Main loop flag
bool quit = false;
//Event handler
SDL_Event e;
//While application is running
while( !quit )
{
//Handle events on queue
while( SDL_PollEvent( &e ) != 0 )
{
//User requests quit
if( e.type == SDL_QUIT )
{
quit = true;
}
}
//Clear screen
SDL_RenderClear( gRenderer );
//Render texture to screen
SDL_RenderCopy( gRenderer, gTexture, NULL, NULL );
//Update screen
SDL_RenderPresent( gRenderer );
}
}
}
//Free resources and close SDL
close();
return 0;
}
Here why are we rendering the effects inside the main loop and make it run again and again rather than like:
int main( int argc, char* args[] )
{
//Start up SDL and create window
if( !init() )
{
printf( "Failed to initialize!\n" );
}
else
{
//Load media
if( !loadMedia() )
{
printf( "Failed to load media!\n" );
}
else
{
//Main loop flag
bool quit = false;
//Event handler
SDL_Event e;
//Clear screen
SDL_RenderClear( gRenderer );
//Render texture to screen
SDL_RenderCopy( gRenderer, gTexture, NULL, NULL );
//Update screen
SDL_RenderPresent( gRenderer );
//While application is running
while( !quit )
{
//Handle events on queue
while( SDL_PollEvent( &e ) != 0 )
{
//User requests quit
if( e.type == SDL_QUIT )
{
quit = true;
}
}
}
}
}
//Free resources and close SDL
close();
return 0;
}
I suppose there is a reason as this is done in many tutorials. But i am unable to get the reason.
You render the screen again and again because typically things represented on the screen are changing. To represent those changes you need to update the display. For example, if a ball is moving across the screen and you only render the screen once, the ball will not appear to move. However, if you continue to "run again and again" then you will be able to see the ball move across the screen.