Scala quasiquote generating parameter default value with backticks

204 views Asked by At

I need to generate:

case class Foo(param: Bar = BarEnum.SomeCaseObject)

But this code:

val term = TermName("BarEnum.SomeCaseObject") 
showCode(q"""case class Foo(val param : Bar = ${term})""") 

outputs the parameter default surrounded by backticks, which doesn't compile:

case class Foo(param: Bar = `BarEnum.SomeCaseObject`)

How can I get the default parameter value output without the backticks?

1

There are 1 answers

0
dveim On BEST ANSWER

You are trying to create value with name "BarEnum.SomeCaseObject", that's illegal identifier, thus in backticks.

You can use Select(Ident(TermName("BarEnum")), TermName("SomeCaseObject")) or (better) q"BarEnum.SomeCaseObject" (assuming that SomeCaseObject is a term).