Reshape data in R change a long table into a wide table

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I would like to use the reshape2 package in R to change my long table into a wide table.

I have a data set from database which is like this (example):

id1   |  id2 |  info  | action_time |
 1    | a    |  info1 |    time1    |
 1    | a    |  info1 |    time2    |  
 1    | a    |  info1 |    time3    |  
 2    | b    |  info2 |    time4    |
 2    | b    |  info2 |    time5    |

And now I want it to be like this:

id1   |  id2 |  info  |action_time 1|action_time 2|action_time 3|
 1    | a    |  info1 |    time1    |    time2    |    time3    |
 2    | b    |  info2 |    time4    |    time5    |             | 

I have tried several times and looked up some examples on some website using reshape() or dcast() but couldn't find such example like this. The number of action_time for each id is different and for some of the ids they may have more than 10 action_times so in that case the reshaped data set will have more than 10 columns of action_time.

Anyone can think of a handy way of doing this? If there is a way of doing this in excel(Pivot Table?) it would be awesome as well. Thank heaps

2

There are 2 answers

3
Steven Beaupré On BEST ANSWER

Try:

library(dplyr)
library(tidyr)

df %>% 
  group_by(id1) %>% 
  mutate(action_no = paste("action_time", row_number())) %>%
  spread(action_no, action_time)

Which gives:

#Source: local data frame [2 x 6]
#
#  id1 id2  info action_time 1 action_time 2 action_time 3
#1   1   a info1         time1         time2         time3
#2   2   b info2         time4         time5            NA

Data

df <- structure(list(id1 = c(1, 1, 1, 2, 2), id2 = structure(c(1L, 
1L, 1L, 2L, 2L), .Label = c("a", "b"), class = "factor"), info = structure(c(1L, 
1L, 1L, 2L, 2L), .Label = c("info1", "info2"), class = "factor"), 
    action_time = structure(1:5, .Label = c("time1", "time2", 
    "time3", "time4", "time5"), class = "factor")), .Names = c("id1", 
"id2", "info", "action_time"), class = "data.frame", row.names = c(NA, -5L))
0
Ricky On

Using tidyr

require(tidyr)
# replicate data
df <- structure(list(id1 = c(1, 1, 1, 2, 2), id2 = structure(c(1L, 
                                                               1L, 1L, 2L, 2L), .Label = c(" a    ", " b    "), class = "factor"), 
                     info = structure(c(1L, 1L, 1L, 2L, 2L), .Label = c("  info1 ", 
                                                                        "  info2 "), class = "factor"), action_time = structure(1:5, .Label = c("    time1    ", 
                                                                                                                                                "    time2    ", "    time3    ", "    time4    ", "    time5    "
                                                                        ), class = "factor")), .Names = c("id1", "id2", "info", "action_time"
                                                                        ), class = "data.frame", row.names = c(NA, -5L))


# create additional column on action_time sequence
action_no <- paste("action_time",
                   unlist(sapply(rle(df$id1)$lengths, function(x) seq(1, x))))
y <- cbind(df, action_no)

# spread into final dataframe
z <- spread(y, action_no, action_time)

Final output

> z
  id1    id2     info action_time 1 action_time 2 action_time 3
1   1  a       info1      time1         time2         time3    
2   2  b       info2      time4         time5              <NA>