To rename the one file in a ZipFile that I'm downloading, I do the following:
for item in zipfile.infolist():
old_name = item.filename
match = re.search(r'(.*)(.mdb)', item.filename)
item.filename = "%s_friend%s" % (match.group(1),, match.group(2)) # I should probably be using replace here
zipfile.extract(old_name, save_dir)
However when I want to extract that file and save it into a specific directory, I need to reference the "old_name" and cannot reference the new. Is there a "cleaner" way of both extracting the renamed file? Or is it more pythonic to first extract and then rename the file?
Like the OP of this SO question, I run into the same error when referencing the renamed file.
updated: This isn't correctly updating the first file. Though it appears to rename the file properly, it output the originally named file.
for item in zipfile.infolist():
old_name = item.filename
match = re.search(r'(.*)(.mdb)', item.filename)
print match.group(1), match.group(2)
item.filename = "%s_%s%s" % (match.group(1), year, match.group(2))
print item.filename
zipfile.close()
with ZipFile(curr_zip, 'r') as zpf:
for item in zpf.infolist():
zpf.extract(item.filename, save_dir)
After testing found that it is not possible to directly rename the file inside a zip folder. All you can do would be to n create a completely new zipfile and add the files back to the new zip file using different name.
Example code for that -