I have a 3rd-party class, say, class A
, and a function accepting vector of class A
from the same 3rd-party, say f3()
(See simplified program below).
For easier use of A
, I created a derived class B
. Many part of my program used class B
.
The question is, how can I call f3()
with a vector of B
as its argument?
Is a forced casting in the argument of f3()
like the program below a good practice?
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;
// a 3rd-party class
class A
{
public:
int n;
void f1();
};
// my class
class B: public A
{
public:
void f2();
};
// a 3rd-party function
void f3(std::vector<A> &a);
int main()
{
std::vector<B> y;
y.push_back(B());
y.push_back(B());
y.push_back(B());
y.push_back(B());
f3(*(vector<A>*)(&y)); // Is this a good practice?
cout << y[3].n << endl;
return 0;
}
Note that, for compatibility, I purposely make class B
to have no more variables than class A
, when B
inherits from A
. However, Class B
does have more methods than A
.
Will it guarantee that sizeof(A)
is the same as sizeof(B)
, so that our cast of vector will work?
I am working on C++03
To answer the question from your code :
No, it's actually a very bad practice , and it will lead to undefined behavior.
If sizeof(A) is equal to sizeof(B) your code might end up working ,considering that all functions derived in B and used inside f3 are virtual and non inline.
If you end up using such code , make sure you will never ever add another virtual function / member variable to the B class .
If you want a way to bypass this limitation (f3 third party function only accepts vector of A ) , try making B a composite rather then a derived (if you are not accessing protected members of A ) :
This way you are isolating the A specific functionality / features.
Ofc you will still need to manually make a vector of A objects made from the objects contained in B (you cannot pass a vector of B).