Regex PHP find 2 words same position

Question

I want to apply a regex to find the English month when i search for the month string in Spanish or other idiom. Currently i have an array of possible matches:

$monthsIdioms = array(
                'en' => array('jan', 'feb', 'mar', 'apr', 'may', 'jun', 'jul', 'aug', 'sep', 'oct', 'nov', 'dec'),    
'es' => array(
            '/ene/',
            '/feb/',
            '/mar/',
            '/abr/',
            '/may/',
            '/jun/',
            '/jul/',
            '/ago/',
            '/sep/',
            '/oct/',
            '/nov/',
            '/dic/'
        ));

But my date variable can have this format:

$date = "24 ene 15:45";

Or this one:

$date = "24 enero 15:45";

So i need a regex to find ene or enero in my date and with the other months:

'es' => array(
                    '/ene|enero/',
                    '/feb|febrero/',
                    '/mar|marzo/',
                    '/abr|abril/',
                    '/may|mayo/',
                    '/jun|junio/',
                    '/jul|julio/',
                    '/ago|agosto/',
                    '/set|septiembre/',
                    '/oct|octubre/',
                    '/nov|noviembre/',
                    '/dic|diciembre/'
                )

And i call this with:

preg_replace($monthsIdioms['es'], $monthsIdioms['en'], $date);

but regex | is not properly working. What i am dong wrong?

Note that 'es' array is regex strings.

So to clarify this, i want that if i have this date: "24 ene 15:45" or this: "24 enero 15:45" to get converted to: "24 jan 15:45" the same with with any other month of the year: "24 ago 15:45" or "24 agosto 15:45" to "24 aug 15:45".

Answer 1

Well since all short names of the month are inside the actual name of the month you could just add a space:

'en' => array('jan ', 'feb ', 'mar ', 'etc'),
'es' => array('/ene |enero /','/feb |febrero /','/mar |marzo / ','etc')