Python: Define own function called "randomcall"

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so i am stuck on a certain problem I have to solve and was wondering if you guys could help me in my situation (i am really new to python and programming by itself). So the task i got is, to define a own new function to pick out of a Dictionary called "phonebook" random people and print out to pretend calling them. Something like "randomcall(phonebook,10) and then it prints: Calling Peter at 1800650, and 9 others.

def randomcall(phonebook, number):
    import random
    
    for name in range(phonebook):
        name = random.choice(list(phonebook))
        phonebook = phonebook[name]
        print(f"Let's call {name} with {phonebook}")

phonebook = {"martin": 12345, "anna": 65478, "klaus": 5468764, "hans": 748463, "peter": 84698416, "ulrich": 3416846546, "frank": 4789749, "lukas": 798469, "ferdinand": 68465131}

randomcall(phonebook, 3)

randomcall("", 5)
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There are 2 answers

0
David On BEST ANSWER

Your code is correct, except for several small mistakes:

  1. As said in my comment above, you cannot use for name in range(phonebook) because phonebook is not the integral number of times that you need to iterate. number is. Also the variable name is not referenced to in the iteration; it was assigned a new value. So it can be changed into another variable, like i, which is used more commonly in iteration.
  2. The number of the person to call is, in your code, stored under the variable phonebook, which is the variable of the phonebook dictionary. It makes it impossible to access the actual phonebook again. Another variable, like phone, can be used there.

So the completed code should look like:

def randomcall(phonebook, number):
    import random

    for name in range(number):
        name = random.choice(list(phonebook))
        phonebook = phonebook[name]
        print(f"Let's call {name} with {phonebook}")


phonebook = {"martin": 12345, "anna": 65478, "klaus": 5468764, "hans": 748463, "peter": 84698416, "ulrich": 3416846546, "frank": 4789749, "lukas": 798469, "ferdinand": 68465131}

randomcall(phonebook, 3)

Output:

Let's call anna with 65478
Let's call klaus with 5468764
Let's call hans with 748463

Also, as stated in this comment, the line randomcall("", 5) is used to call a random person. Actually, the phonebook must be passed to the function as the phonebook parameter, and if 1 is passed to the number parameter, it generates 1 random call.

0
Ice Bear On

You could this, number will be the range on how many people to call.

import random

def randomcall(phonebook,number):

    for _ in range(number):
        name = random.choice(list(phonebook.keys()))
        print(f'Lets call {name} with {phonebook[name]}')



phonebook = {"martin":12345,"anna":65478,"klaus":5468764,"hans":748463,"peter":84698416,"ulrich":3416846546,"frank":4789749,"lukas":798469,"ferdinand":68465131}

randomcall(phonebook,3)

Output:

Lets call lukas with 798469
Lets call peter with 84698416
Lets call klaus with 5468764