Python CGIHTTPServer set file types for dynamic vs static pages

Question

This question (Python CGIHTTPServer Default Directories) details how to set paths for location of cgi-bin files for Python CGIHTTPServer. From testing this, it seems that you cannot mix .py and .html files in the same folder: in cgi-bin it processes .py files fine, but asked to serve a static html file I get

127.0.0.1 - - [08/Jan/2017 10:51:22] "GET /dev.html HTTP/1.1" 200 -
Traceback (most recent call last):
   File "/usr/lib/python2.7/CGIHTTPServer.py", line 248, in run_cgi
      os.execve(scriptfile, args, env)
OSError: [Errno 8] Exec format error
127.0.0.1 - - [08/Jan/2017 10:51:22] CGI script exit status 0x7f00

Is this the real intended behaviour, or am I missing something? The sparse and opaque documentation says "The class will however, run the CGI script, instead of serving it as a file, if it guesses it to be a CGI script. Only directory-based CGI are used — the other common server configuration is to treat special extensions as denoting CGI scripts."

How do I do "treat special extensions as denoting CGI scripts". What method or setting do I use, or which magic words do I utter? Or is this just an ineptly worded tip-off that I just can't do it?

I'm only using this for quick tests, and while I could restructure to separate .py and .html files I have other constraints that would make this a painful exercise.

Answer 1

I took oryginal is_cgi() from CGIHTTPServer.py and add two elements

• CGIHTTPServer. in CGIHTTPServer._url_collapse_path(self.path) to use it outside file CGIHTTPServer.py

• and more important: checking extension

  if not tail.endswith('.html'):
  

  but it could be done better.

I didn't use

    if tail.endswith('.py'):

because server may execute scripts in other languages if you need - ie. Perl, PHP, Bash, etc.

Code:

import BaseHTTPServer
import CGIHTTPServer

class MyHandler(CGIHTTPServer.CGIHTTPRequestHandler):

    # code from oryginal CGIHTTPServer.py
    def is_cgi(self):
        #                v added `CGIHTTPServer.`
        collapsed_path = CGIHTTPServer._url_collapse_path(self.path) 
        dir_sep = collapsed_path.find('/', 1)
        head, tail = collapsed_path[:dir_sep], collapsed_path[dir_sep+1:]
        if head in self.cgi_directories:
            if not tail.endswith('.html'): # <-- new line
            #if tail.endswith('.py'): # <-- new line
                self.cgi_info = head, tail
                return True
        return False

# --- test ---

MyHandler.cgi_directories = ['/']

server = BaseHTTPServer.HTTPServer(('', 8000), MyHandler)
server.serve_forever()

Answer 2

You need to detect, what kind of file type is requested (py/cgi or a static file). Mimetypes may help. When a static file is requested, you could call another cgi script that delivers your static file. Btw. you should use wsgi instead of outdated cgi.

I modified some old code (py2.7) i got - that's very ugly and i never used it - but when you put a static file 'dev.html' in the 'handler.cgi_directory' it should be served by static.py.

server.py:

#!/usr/bin/python2
import BaseHTTPServer
import CGIHTTPServer
from mimetypes import MimeTypes
import urllib 

class handler(CGIHTTPServer.CGIHTTPRequestHandler):  
    def is_cgi(self):
        mime = MimeTypes()
        request = self.path.split('?')
        if len(request) == 2:
            path, args = request
        else:
            path, args = request, None

        if isinstance(path, list):
            path = path[0]

        url = urllib.pathname2url(path)
        mime_type = mime.guess_type(url)

        if 'python' in mime_type[0]:
            self.cgi_info = '', self.path[1:]
            return True
        else:
            self.cgi_info = '', '/static.py?path=%s' % path[1:]
            print self.cgi_info
            return True

server = BaseHTTPServer.HTTPServer
server_address = ("", 8000)
handler.cgi_directories = ["/somedir/..."]

httpd = server(server_address, handler)
httpd.serve_forever()

static.py:

#!/usr/bin/python2

import cgi
import urllib
from mimetypes import MimeTypes

form = cgi.FieldStorage()
mime = MimeTypes()

path = form.getvalue('path')

url = urllib.pathname2url(path)
mime_type = mime.guess_type(url)

print """Content-type: %s""" % mime
print 
print open(path, 'r').read()