I am trying to parse a String
using SimpleDateFormat
.
This is my current code:
public String getCreatedDateTime() {
SimpleDateFormat simpleDateFormat = new SimpleDateFormat("yyyy-MM-ddEHH:mm:ss.zzzz");
try {
Date date = simpleDateFormat.parse("2015-06-27T13:16:37.363Z");
return date.toString();
} catch (ParseException e) {
return "Error parsing date";
}
}
As you can see, I just put a constant in the parse() method for testing purposes.
So, this is what I am trying to parse:
2015-06-27T13:16:37.363Z
This is the SimpleDateFormat
pattern that I am using:
yyyy-MM-ddEHH:mm:ss.zzzz
I keep getting the ParseException.
I know that it is proably because of the .zzzz at the end but I have no idea what .363Z might stand for so I just used some random letters. Bad idea.
I'll appreciate your help a lot. Thank you!
Try with this pattern (note the X at the end and the 'T' in the middle):
From Java's SimpleDateFormat's documentation:
And, from the part where it describes the different characters:
EDIT
If using Android, then "X" is not supported.
You can use this pattern (note Z is a literal now):
But then you'll get the date on your current timezone and would need to convert it to UTC if needed.