The following code
if (Double.parseDouble(value) > 0)
throws the following exception
java.lang.NumberFormatException: Invalid double: "-2.49"
The logged value seems like a valid Double, what might cause this exception?
parseDouble exception on Android while parsing a valid Double value
811 views Asked by Guy Levinger At
1
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You seem to encounter a locale issue. That is, integer and fractional part separators differ in different locales, somewhere it's
.and somewhere,.See that question, there's a probable solution. Use the locale which fits the best for you, for example
Locale.USuses.as the separator.