What would be another way to write the code below?
li $t1, 1 # load 1 in register $t1
sll $t1, $t1, 23 # shift value of 1 to the 24th bit to get 1000 0000 0000 0000 0000 0000
I am concerned that this code does not not actually shift 1 to the 24th bit. So what would be another way to write it?
Thanks in advance.