I'm using matplotlib's specgram
function to generate a spectrogram. I've attempted to include a colorbar off to the right of the spectrogram to give an indication of dB-to-color-mapping.
For some reason though, the dB indicated by the colorbar do not make sense.
Perhaps I've not generated the colorbar correctly? Perhaps there is some parameter that I need to pass to specgram?
The signal I'm generating is a 1Khz, 2Vpp sine sampled at 32Khz.
I'm expecting that the dark red peak on the spectrogram corresponds to 0dB (Meaning that +1V is my reference)
Anybody have any idea what is wrong with my approach?
def plot_specgram(data, title='', x_label='', y_label='', fig_size=None):
fig = plt.figure()
if fig_size != None:
fig.set_size_inches(fig_size[0], fig_size[1])
ax = fig.add_subplot(111)
ax.set_title(title)
ax.set_xlabel(x_label)
ax.set_ylabel(y_label)
pxx, freq, t, cax = plt.specgram(data, Fs=32000)
fig.colorbar(cax).set_label('Intensity [dB]')
plot_specgram(a,title='Spectrogram', x_label='time (in seconds)', y_label='frequency', fig_size=(14,8))
This is what I get as resulting spectrogram:
First of all, please supply your
a
vector, since it seems to have some kind of harmonics.This is a bit trial and error, but this seems to produce the correct scaling:
Using a window seems to lose about 1/2 of the peak power, you can of course adjust for this.
A complete example where I have limited the dynamic range to 40dB (as an example, if you want to hide the small stuff).