Can someone point me what is wrong in this code ?
Html:
<!DOCTYPE html >
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Insert title here</title>
</head>
<script type="text/javascript" src="js/jquery-1.7.1.js"></script>
<style type="text/css">@import "js/jquery.svg/jquery.svg.css";</style>
<script type="text/javascript" src="js/jquery.svg/jquery.svg.js"></script>
<script type="text/javascript" src="js/svg.js"></script>
<body>
<div id="svgintro" style="height:800px"></div>
</body>
</html>
JavaScript:
var defs=svg.defs();
svg.linearGradient(defs, 'gradient', [[0, 'white', 1], [1, 'red', 1]], 0, 0, 0, 100, {gradientUnits: 'userSpaceOnUse'});
svg.rect(20, 400, 1500, 40, 10, 10, {fill:'url(#gradient)'});
It always show one color.
Thank you.
Solution:
svg.linearGradient(defs, 'gradient', [['0%', 'white'], ['100%', 'red']], 20, 400, 20, 440, {gradientUnits: 'userSpaceOnUse'});
The problem here, as far as I can tell, is that the
x1, y1, x2, y2attributes oflinearGradientare in absolute coordinates, not relative to the object you're applying the gradient to. So your gradient ends aty:100but the top of your rectangle is aty:400, so it only gets the red part of the gradient applied.See http://jsfiddle.net/nrabinowitz/VTKj2/1/ for an example, showing that a rectangle with the top at
y:20has the gradient properly applied.