I'm playing around with OR Tools, just wondering if there is any way to hold the number of times a certain constraint is satisfied?
In this case, I'd like to keep track of the number of times my 'diff' variable is -1, -2, 0, 2 , etc.
I've gotten the solution printer from the official documentation, so would I have to edit/tweak that in any way to return count as well?
Thanks in advance, I'm new to this.
from ortools.sat.python import cp_model
model = cp_model.CpModel()
x = model.NewIntVar(0, 10, 'x')
y = model.NewIntVar(0, 10, 'y')
diff = model.NewIntVar(-10,10,'diff')
model.Add(diff == x - y)
#occurences of each diff
#solution printer
class VarArraySolutionPrinter(cp_model.CpSolverSolutionCallback):
"""Print intermediate solutions."""
def __init__(self, variables):
cp_model.CpSolverSolutionCallback.__init__(self)
self.__variables = variables
self.__solution_count = 0
def on_solution_callback(self):
self.__solution_count += 1
for v in self.__variables:
print(f"{v}={self.Value(v)}", end=" ")
print()
def solution_count(self):
return self.__solution_count
solver = cp_model.CpSolver()
# solver.parameters.log_search_progress = True
solution_printer = VarArraySolutionPrinter([x, y, diff])
solver.parameters.enumerate_all_solutions = True
status = solver.Solve(model, solution_printer)
Why don't you just increase a counter in the on_solution_callback() method ?