Assume a computer with a 16-bit memory and 16-bit data and address bus. So if an Instruction is of 16-bit let's say the opcode occupies 6 bits and the operand occupies the remaining 10 bits. In the direct addressing mode, the memory address of the operand is specified in the instruction itself. So how a 16-bit memory location is specified inside the 10-bit instruction operand. Is the address encoded somehow or one Instruction is stored in multiple memory locations? Sorry, If my question seems kind of stupid.
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