I don't understand the pattern of CheckBox click with the new parameter

62 views Asked by At

The following code is used to toggle the CheckBox in order to make the user able to see his password :

passwordCheckBox.setOnCheckedChangeListener(new CompoundButton.OnCheckedChangeListener() {

    @Override 
    public void onCheckedChanged(CompoundButton buttonView, boolean isChecked) {

        if (!isChecked) {
            passwordEditText.setInputType(TYPE_CLASS_TEXT | TYPE_TEXT_VARIATION_PASSWORD);
            passwordConfirmEditText.setInputType(TYPE_CLASS_TEXT | TYPE_TEXT_VARIATION_PASSWORD);
        } else {
            passwordEditText.setInputType(TYPE_CLASS_TEXT | TYPE_TEXT_VARIATION_VISIBLE_PASSWORD);
            passwordConfirmEditText.setInputType(TYPE_CLASS_TEXT | TYPE_TEXT_VARIATION_VISIBLE_PASSWORD);
        }
    }
});

Here is what I understand from above: there's a CheckBox named passwordCheckBox, I'd set a listener to the CheckBox as soon as I click on it in order to (un)Toggle the CheckBox, if it's not Checked, passwordEditText won't appear as characters, if it's Checked password will appear as characters. If I am mistaken in what I assume, correct me please.

I don't understand the pattern of this code, How can the parameter "isChecked" which should be a new variable(?), be understood by the application where the isChecked is equal to "True" (And at the same time it's understood as it's the user input)

1

There are 1 answers

0
hellohello On BEST ANSWER

This is the answer: @hellohello That construct is called an anonymous class. OnCheckedChanged is not called by your code, it's called by Android internal code only when the user interacts with the checkbox. – Christian Strempfer

All thanks for other comments