Given the following instruction:
addi $s0, $0, −10
I need to compute it's 32-bit representation. Since addi is I-type instruction
the opcode for addi is 001000.
Rs is $0, which is 00000
Rt os $s0, which is 10000
how do i compute the remaining 16 bit for -10? I converted 10 to binary and found its one's and two's complement and added a 1 (negative bit) to the leftmost side.
I got 001000 00000 10000 1000000011110110 which translates to 0x201080F6, but it is incorrect.
What am i doing wrong?