My code is below: dept_id and desi_id is the field of entries3 views.py
def claim(request):
entries = Child_Info.objects.all()
entries2 = Employee.objects.filter(emp_name='Suresh Babubhai Vekariya')
entries3 = Emp_Department.objects.filter(emp_no=12345)
for a in entries3:
dept_id = a.dept_id;
desi_id = a.desi_id
print dept_id
ctx = { 'entries' : entries ,'entries2' : entries2 }
return render_to_response('myapp/claim.html', ctx)
Here are that 3 models:
class Department(models.Model):
dept_id = models.CharField(primary_key=True,max_length=20,unique=True)
dept_name = models.CharField(max_length=20)
dept_add = models.CharField(max_length=30)
def _str_(self):
return self.dept_id
class Emp_Department(models.Model):
emp_no = models.ForeignKey(Employee)
dept_id = models.ForeignKey(Department)
emp_type = models.CharField(max_length=30)
desi_id = models.CharField(max_length=30)
join_date = models.DateField()
retire_date = models.DateField()
def _str_(self):
return "%s,%s,%s" %(self.desi_id,self.dept_id,self.emp_no)
class Designation(models.Model):
desi_id = models.CharField(primary_key=True,max_length=30)
dept_id = models.ForeignKey(Department)
title = models.CharField(max_length=20)
def _str_(self):
return "%s,%s,%s" %(self.desi_id,self.dept_id,self.title)
I want to fetch title from designation and dept_name from Department
You have already filtered the results on the basis of a particular field.
In case you are trying to ask as to how to display a particular field in the template then in your claim.html file, try the following:
This will display the emp_name of the first employee. Similarly, you can replace emp_name with whatever field you want to display inside the template.
I hope this is what you wanted to ask because the question is not quite clear.